* [1] states: "For 1/2 < h < 1 the bottom left element of the matrix
* should be (1 - 2*h^m + (2h - 1)^m )/m!" Since 0 <= h < 1, then if h >
* 1/2 is sufficient to check:
*/
if (h.compareTo(BigFraction.ONE_HALF) == 1) {
Hdata[m - 1][0] = Hdata[m - 1][0].add(h.multiply(2).subtract(1).pow(m));
}
/*
* Aside from the first column and last row, the (i, j)-th element is
* 1/(i - j + 1)! if i - j + 1 >= 0, else 0. 1's and 0's are already