Examples of java.awt.geom.Rectangle2D.outcode()

java.awt.geom.Rectangle2D.outcode()
Determines where the specified coordinates lie with respect to this Rectangle2D. This method computes a binary OR of the appropriate mask values indicating, for each side of this Rectangle2D, whether or not the specified coordinates are on the same side of the edge as the rest of this Rectangle2D. @param x the specified X coordinate @param y the specified Y coordinate @return the logical OR of all appropriate out codes. @see #OUT_LEFT @see #OUT_TOP @see #OUT_RIGHT @see #OUT_BOTTOM @since 1.2

  public void testOutcode() {
    Point2D pInexact = new Point2D.Double(), pExact = new Point2D.Double();
    Rectangle2D rect = new Rectangle2D.Double(0, 0, 10, 10);
    pExact.setLocation(10, 5);
    pInexact.setLocation(10.00001, 5.00001);
    assertEquals("regular outcode() says outside", 4, rect.outcode(pInexact));
    assertEquals("custom outcode() should say inside", 0,
      GeometryUtil.getInstance().outcode(rect, pInexact));
  }


  /**

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        // <<<< Get visible line candidates of these obstacles >>>>
        Vector<Line2D> visibleLineCandidates = new Vector<Line2D>();
        for (int i=0; i < visibleObstacleCandidates.size(); i++) {
          Rectangle2D obstacle = visibleObstacleCandidates.get(i);
          int outcode = obstacle.outcode(source);


          if ((outcode & Rectangle2D.OUT_BOTTOM) != 0) {
            visibleLineCandidates.add(
                new Line2D.Double(obstacle.getMinX(), obstacle.getMaxY(), obstacle.getMaxX(), obstacle.getMaxY()));
          }

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     *   Right and above are prioritized higher than left and below.
     * @return
     */
    private static final <G,V> InnerNode<G,V> growUp(DynamicQuadTree.InnerNode<G,V> current, Rectangle2D toward) {
      Rectangle2D currentBounds = current.concernBounds();
      int outCode = currentBounds.outcode(toward.getX(), toward.getY());
      
      if (toward.intersects(currentBounds)
          || outCode ==0) { 
        //If the new glyph touches the current bounds, then grow with the current data in the center. 
        Rectangle2D newBounds = new Rectangle2D.Double(

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        // <<<< Get visible line candidates of these obstacles >>>>
        Vector<Line2D> visibleLineCandidates = new Vector<Line2D>();
        for (int i=0; i < visibleObstacleCandidates.size(); i++) {
          Rectangle2D obstacle = visibleObstacleCandidates.get(i);
          int outcode = obstacle.outcode(source);


          if ((outcode & Rectangle2D.OUT_BOTTOM) != 0) {
            visibleLineCandidates.add(
                new Line2D.Double(obstacle.getMinX(), obstacle.getMaxY(), obstacle.getMaxX(), obstacle.getMaxY()));
          }

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