Examples of multiplyBaseCostByOuterRows()

Examples of org.apache.derby.iapi.sql.compile.JoinStrategy.multiplyBaseCostByOuterRows()

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      ** using the unique index. This is probably OK most of the
      ** time, since the optimizer would probably choose the
      ** unique index, anyway. But it would be better if the
      ** optimizer set the row count properly in this case.
      */
      if (currentJoinStrategy.multiplyBaseCostByOuterRows())
      {
        newCost *= outerCost.rowCount();
      }

      rowCount *= outerCost.rowCount();
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Examples of org.apache.derby.iapi.sql.compile.JoinStrategy.multiplyBaseCostByOuterRows()

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      ** NOTE: The multiplication should only be done against the
      ** total row count, not the singleScanRowCount.
      */
      double newCost = costEstimate.getEstimatedCost();

      if (currentJoinStrategy.multiplyBaseCostByOuterRows())
      {
        newCost *= outerCost.rowCount();
      }

      costEstimate.setCost(
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Examples of org.apache.derby.iapi.sql.compile.JoinStrategy.multiplyBaseCostByOuterRows()

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        ** multiplyBaseCostByOuterRows() will return false.
        */
        double rowsTouched = costEstimate.rowCount();

        if ( (! constantStartStop) &&
           currentJoinStrategy.multiplyBaseCostByOuterRows())
        {
          /*
          ** This is a join where the inner table is scanned
          ** more than once, so we have to take the number
          ** of outer rows into account.  The formula for this
View Full Code Here

Examples of org.apache.derby.iapi.sql.compile.JoinStrategy.multiplyBaseCostByOuterRows()

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      ** using the unique index. This is probably OK most of the
      ** time, since the optimizer would probably choose the
      ** unique index, anyway. But it would be better if the
      ** optimizer set the row count properly in this case.
      */
      if (currentJoinStrategy.multiplyBaseCostByOuterRows())
      {
        newCost *= outerCost.rowCount();
      }

      rowCount *= outerCost.rowCount();
View Full Code Here

Examples of org.apache.derby.iapi.sql.compile.JoinStrategy.multiplyBaseCostByOuterRows()

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      ** NOTE: The multiplication should only be done against the
      ** total row count, not the singleScanRowCount.
      */
      double newCost = costEstimate.getEstimatedCost();

      if (currentJoinStrategy.multiplyBaseCostByOuterRows())
      {
        newCost *= outerCost.rowCount();
      }

      costEstimate.setCost(
View Full Code Here

Examples of org.apache.derby.iapi.sql.compile.JoinStrategy.multiplyBaseCostByOuterRows()

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        ** multiplyBaseCostByOuterRows() will return false.
        */
        double rowsTouched = costEstimate.rowCount();

        if ( (! constantStartStop) &&
           currentJoinStrategy.multiplyBaseCostByOuterRows())
        {
          /*
          ** This is a join where the inner table is scanned
          ** more than once, so we have to take the number
          ** of outer rows into account.  The formula for this
View Full Code Here

Examples of org.apache.derby.iapi.sql.compile.JoinStrategy.multiplyBaseCostByOuterRows()

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      ** using the unique index. This is probably OK most of the
      ** time, since the optimizer would probably choose the
      ** unique index, anyway. But it would be better if the
      ** optimizer set the row count properly in this case.
      */
      if (currentJoinStrategy.multiplyBaseCostByOuterRows())
      {
        newCost *= outerCost.rowCount();
      }

      rowCount *= outerCost.rowCount();
View Full Code Here

Examples of org.apache.derby.iapi.sql.compile.JoinStrategy.multiplyBaseCostByOuterRows()

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      ** NOTE: The multiplication should only be done against the
      ** total row count, not the singleScanRowCount.
      */
            double newCost = costEst.getEstimatedCost();

      if (currentJoinStrategy.multiplyBaseCostByOuterRows())
      {
        newCost *= outerCost.rowCount();
      }

            costEst.setCost(
View Full Code Here

Examples of org.apache.derby.iapi.sql.compile.JoinStrategy.multiplyBaseCostByOuterRows()

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        ** multiplyBaseCostByOuterRows() will return false.
        */
                double rowsTouched = costEst.rowCount();

        if ( (! constantStartStop) &&
           currentJoinStrategy.multiplyBaseCostByOuterRows())
        {
          /*
          ** This is a join where the inner table is scanned
          ** more than once, so we have to take the number
          ** of outer rows into account.  The formula for this
View Full Code Here

Examples of org.apache.derby.iapi.sql.compile.JoinStrategy.multiplyBaseCostByOuterRows()

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      ** using the unique index. This is probably OK most of the
      ** time, since the optimizer would probably choose the
      ** unique index, anyway. But it would be better if the
      ** optimizer set the row count properly in this case.
      */
      if (currentJoinStrategy.multiplyBaseCostByOuterRows())
      {
        newCost *= outerCost.rowCount();
      }

            rowCnt *= outerCost.rowCount();
View Full Code Here
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