Examples of java.math.BigInteger.shiftLeft()

java.math.BigInteger.shiftLeft()
Returns a BigInteger whose value is {@code (this << n)}. The shift distance, {@code n}, may be negative, in which case this method performs a right shift. (Computes floor(this * 2ⁿ).) @param n shift distance, in bits. @return {@code this << n} @see #shiftRight

    BigInteger b = new BigInteger(new byte[]{0x00,data[offset+1]});
    BigInteger c = new BigInteger(new byte[]{0x00,data[offset+2]});
    BigInteger d = new BigInteger(new byte[]{0x00,data[offset+3]});
    b = b.shiftLeft(8);
    c = c.shiftLeft(16);
    d = d.shiftLeft(24);


    return a.longValue() + b.longValue() + c.longValue() + d.longValue();
  }

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                if (k.testBit(j))
                {
                    Qh = Ql.multiply(Q).mod(p);
                    Uh = Uh.multiply(Vh).mod(p);
                    Vl = Vh.multiply(Vl).subtract(P.multiply(Ql)).mod(p);
                    Vh = Vh.multiply(Vh).subtract(Qh.shiftLeft(1)).mod(p);
                }
                else
                {
                    Qh = Ql;
                    Uh = Uh.multiply(Vl).subtract(Ql).mod(p);

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        BigInteger big = BigInteger.ZERO;
        for (int i = 0; i < str.length(); i++)
        {
            int charpos = 16 * (sigchars - (i + 1));
            BigInteger charbig = BigInteger.valueOf(str.charAt(i) & 0xFFFF);
            big = big.or(charbig.shiftLeft(charpos));
        }
        return big;
    }


    /**

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        BigInteger big = BigInteger.ZERO;
        for (int i = 0; i < str.length(); i++)
        {
            int charpos = 16 * (sigchars - (i + 1));
            BigInteger charbig = BigInteger.valueOf(str.charAt(i) & 0xFFFF);
            big = big.or(charbig.shiftLeft(charpos));
        }
        return big;
    }


    /**

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        BigInteger big = BigInteger.ZERO;
        for (int i = 0; i < str.length(); i++)
        {
            int charpos = 16 * (sigchars - (i + 1));
            BigInteger charbig = BigInteger.valueOf(str.charAt(i) & 0xFFFF);
            big = big.or(charbig.shiftLeft(charpos));
        }
        return big;
    }


    /**

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        BigInteger big = BigInteger.ZERO;
        for (int i = 0; i < str.length(); i++)
        {
            int charpos = 16 * (sigchars - (i + 1));
            BigInteger charbig = BigInteger.valueOf(str.charAt(i) & 0xFFFF);
            big = big.or(charbig.shiftLeft(charpos));
        }
        return big;
    }


    /**

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        BigInteger big = BigInteger.ZERO;
        for (int i = 0; i < str.length(); i++)
        {
            int charpos = 16 * (sigchars - (i + 1));
            BigInteger charbig = BigInteger.valueOf(str.charAt(i) & 0xFFFF);
            big = big.or(charbig.shiftLeft(charpos));
        }
        return big;
    }


    /**

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                mantissa = -mantissa;
            }
            exp -= 1075;
            BigInteger x = BigInteger.valueOf(mantissa);
            if (exp > 0) {
                x = x.shiftLeft(exp);
            } else if (exp < 0) {
                x = x.shiftRight(-exp);
            }
            intDigits = x.toString(base);
        }

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                mhi = BigInteger.valueOf(1<<Log2P);
            }


            b = b.shiftLeft(e[0] + s2);
            BigInteger s = BigInteger.valueOf(1);
            s = s.shiftLeft(s2);
            /* At this point we have the following:
             *   s = 2^s2;
             *   1 > df = b/2^s2 > 0;
             *   (d - prevDouble(d))/2 = mlo/2^s2;
             *   (nextDouble(d) - d)/2 = mhi/2^s2. */

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            m2 += i;
            s2 += i;
        }
        /* Now S*2^s2 has exactly four leading zero bits in its most significant word. */
        if (b2 > 0)
            b = b.shiftLeft(b2);
        if (s2 > 0)
            S = S.shiftLeft(s2);
        /* Now we have d/10^k = b/S and
           (mhi * 2^m2) / S = maximum acceptable error, divided by 10^k. */
        if (k_check) {

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