List of divideAndRemainder() Examples

Examples of divideAndRemainder()

java.math.BigDecimal.divideAndRemainder()
Returns a two-element {@code BigDecimal} array containing theresult of {@code divideToIntegralValue} followed by the result of{@code remainder} on the two operands.
Note that if both the integer quotient and remainder are needed, this method is faster than using the {@code divideToIntegralValue} and {@code remainder} methodsseparately because the division need only be carried out once. @param divisor value by which this {@code BigDecimal} is to be divided, and the remainder computed. @return a two element {@code BigDecimal} array: the quotient (the result of {@code divideToIntegralValue}) is the initial element and the remainder is the final element. @throws ArithmeticException if {@code divisor==0} @see #divideToIntegralValue(java.math.BigDecimal,java.math.MathContext) @see #remainder(java.math.BigDecimal,java.math.MathContext) @since 1.5
java.math.BigInteger.divideAndRemainder()
Returns an array of two BigIntegers containing {@code (this / val)}followed by {@code (this % val)}. @param val value by which this BigInteger is to be divided, and theremainder computed. @return an array of two BigIntegers: the quotient {@code (this / val)}is the initial element, and the remainder {@code (this % val)}is the final element. @throws ArithmeticException {@code val==0}

Examples of java.math.BigInteger.divideAndRemainder()

            // Check if we can strip off any trailing zeros after decimal point
            BigInteger i = value.unscaledValue();
            int limit = value.scale();
            int nshift = 0;
            for (nshift = 0; nshift < limit; nshift++) {
                BigInteger[] quotRem = i.divideAndRemainder(ten);
                if (quotRem[REM].intValue() != 0) break;
                i = quotRem[QUOT];
            }
            if (nshift > 0) {
               value = new BigDecimal(i, limit - nshift);

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Examples of java.math.BigInteger.divideAndRemainder()

            }
            /* mlo/S = maximum acceptable error, divided by 10^k, if the output is less than d. */
            /* mhi/S = maximum acceptable error, divided by 10^k, if the output is greater than d. */


            for(i = 1;;i++) {
                BigInteger[] divResult = b.divideAndRemainder(S);
                b = divResult[1];
                dig = (char)(divResult[0].intValue() + '0');
                /* Do we yet have the shortest decimal string
                 * that will round to d?
                 */

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Examples of java.math.BigInteger.divideAndRemainder()

            }
        }
        else
            for(i = 1;; i++) {
//                (char)(dig = quorem(b,S) + '0');
                BigInteger[] divResult = b.divideAndRemainder(S);
                b = divResult[1];
                dig = (char)(divResult[0].intValue() + '0');
                buf.append(dig);
                if (i >= ilim)
                    break;

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Examples of java.math.BigInteger.divideAndRemainder()

        if (sdv.negative) {
            seconds = seconds.negate();
        }
        BigDecimal microseconds = seconds.multiply(DecimalValue.BIG_DECIMAL_ONE_MILLION);
        BigInteger intMicros = microseconds.toBigInteger();
        BigInteger[] parts = intMicros.divideAndRemainder(BigInteger.valueOf(1000000));
        sdv.seconds = parts[0].longValue();
        sdv.microseconds = parts[1].intValue();
        return sdv;
    }

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Examples of java.math.BigInteger.divideAndRemainder()


        int scale = value.scale();
        if (scale > 0) {
            BigInteger i = value.unscaledValue();
            while (true) {
                BigInteger[] dr = i.divideAndRemainder(BIG_INTEGER_TEN);
                if (dr[1].equals(BigInteger.ZERO)) {
                    i = dr[0];
                    scale--;
                    if (scale==0) {
                        break;

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Examples of java.math.BigInteger.divideAndRemainder()

            }
            /* mlo/S = maximum acceptable error, divided by 10^k, if the output is less than d. */
            /* mhi/S = maximum acceptable error, divided by 10^k, if the output is greater than d. */


            for(i = 1;;i++) {
                BigInteger[] divResult = b.divideAndRemainder(S);
                b = divResult[1];
                dig = (char)(divResult[0].intValue() + '0');
                /* Do we yet have the shortest decimal string
                 * that will round to d?
                 */

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Examples of java.math.BigInteger.divideAndRemainder()

            }
        }
        else
            for(i = 1;; i++) {
//                (char)(dig = quorem(b,S) + '0');
                BigInteger[] divResult = b.divideAndRemainder(S);
                b = divResult[1];
                dig = (char)(divResult[0].intValue() + '0');
                buf.append(dig);
                if (i >= ilim)
                    break;

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Examples of java.math.BigInteger.divideAndRemainder()

        if (multiplicand == 1) {
            return this;
        }
        BigInteger nanos = toNanos();
        nanos = nanos.multiply(BigInteger.valueOf(multiplicand));
        BigInteger[] divRem = nanos.divideAndRemainder(Instant.BILLION);
        if (divRem[0].bitLength() > 63) {
            throw new ArithmeticException("Multiplication result exceeds capacity of Duration: " + this + " * " + multiplicand);
        }
        return seconds(divRem[0].longValue(), divRem[1].intValue());
     }

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Examples of java.math.BigInteger.divideAndRemainder()

        if (divisor == 1) {
            return this;
        }
        BigInteger nanos = toNanos();
        nanos = nanos.divide(BigInteger.valueOf(divisor));
        BigInteger[] divRem = nanos.divideAndRemainder(Instant.BILLION);
        return seconds(divRem[0].longValue(), divRem[1].intValue());
     }


    //-----------------------------------------------------------------------
    /**

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Examples of java.math.BigInteger.divideAndRemainder()

            }
            /* mlo/S = maximum acceptable error, divided by 10^k, if the output is less than d. */
            /* mhi/S = maximum acceptable error, divided by 10^k, if the output is greater than d. */


            for(i = 1;;i++) {
                BigInteger[] divResult = b.divideAndRemainder(S);
                b = divResult[1];
                dig = (char)(divResult[0].intValue() + '0');
                /* Do we yet have the shortest decimal string
                 * that will round to d?
                 */

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