Examples of ConvergenceException

net.sf.doodleproject.numerics4j.exception.ConvergenceException
The exception raised when an iterative method fails to converge. @version $Revision: 1.2 $ $Date: 2007/10/25 04:44:18 $
org.apache.commons.math.ConvergenceException
Error thrown when a numerical computation can not be performed because the numerical result failed to converge to a finite value. @version $Revision: 983921 $ $Date: 2010-08-10 12:46:06 +0200 (mar. 10 août 2010) $
org.apache.commons.math.exception.ConvergenceException
Error thrown when a numerical computation can not be performed because the numerical result failed to converge to a finite value. @since 2.2 @version $Revision: 1026666 $ $Date: 2010-10-23 21:30:48 +0200 (sam. 23 oct. 2010) $
org.apache.commons.math3.exception.ConvergenceException
Error thrown when a numerical computation can not be performed because the numerical result failed to converge to a finite value. @since 2.2

Examples of org.apache.commons.math3.exception.ConvergenceException

                }


                // tests for termination and stringent tolerances
                // (2.2204e-16 is the machine epsilon for IEEE754)
                if ((FastMath.abs(actRed) <= 2.2204e-16) && (preRed <= 2.2204e-16) && (ratio <= 2.0)) {
                    throw new ConvergenceException(LocalizedFormats.TOO_SMALL_COST_RELATIVE_TOLERANCE,
                                                   costRelativeTolerance);
                } else if (delta <= 2.2204e-16 * xNorm) {
                    throw new ConvergenceException(LocalizedFormats.TOO_SMALL_PARAMETERS_RELATIVE_TOLERANCE,
                                                   parRelativeTolerance);
                } else if (maxCosine <= 2.2204e-16)  {
                    throw new ConvergenceException(LocalizedFormats.TOO_SMALL_ORTHOGONALITY_TOLERANCE,
                                                   orthoTolerance);
                }
            }
        }
    }

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Examples of org.apache.commons.math3.exception.ConvergenceException

                for (int j = k; j < nR; ++j) {
                    double aki = weightedJacobian[j][permutation[i]];
                    norm2 += aki * aki;
                }
                if (Double.isInfinite(norm2) || Double.isNaN(norm2)) {
                    throw new ConvergenceException(LocalizedFormats.UNABLE_TO_PERFORM_QR_DECOMPOSITION_ON_JACOBIAN,
                                                   nR, nC);
                }
                if (norm2 > ak2) {
                    nextColumn = i;
                    ak2        = norm2;

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