// subscribe request, nothing much we can do in this case
return;
}
if (topicSub2Channel.containsKey(topicSubscriber)) {
TopicBusyException pse = new PubSubException.TopicBusyException(
"subscription for this topic, subscriberId is already being served on a different channel");
throw pse;
}
topicSub2Channel.put(topicSubscriber, channel);