Package jpa.controllers

Examples of jpa.controllers.UserJpaController

40
41
42
43
44
45
46
47
48
49
50
51
        String userEmail = request.getParameter("email");
        String userPassword = request.getParameter("password");
        String result = "";
        User user = null;
       
        UserJpaController jpaController = new UserJpaController();
        user = jpaController.loginUser(userEmail, userPassword);
       
        if(user != null) {
            result = "login_successful";
        }
       
View Full Code Here
20
21
22
23
24
25
26
27
    public Object getAsObject(FacesContext context, UIComponent component, String value) {
        if (value == null || value.length() == 0) {
            return null;
        }
        Integer id = new Integer(value);
        UserJpaController controller = (UserJpaController) context.getApplication().getELResolver().getValue(context.getELContext(), null, "userJpa");
        return controller.findUser(id);
    }
View Full Code Here
42
43
44
45
46
47
48
49
50
        em = emf.createEntityManager();
    }
   
   @Test
   public void testAuthenticateInvalidUser() {
       UserJpaController service = new UserJpaController(emf);
       boolean result = service.authenticateUser("ata@gmail.com", "dddss", s1);
       Assert.assertFalse(result);
   }
View Full Code Here
TOP

Related Classes of jpa.controllers.UserJpaController

  • entity.test.UserTest
  • entity.User
  • jsf.entity.UserConverter
  • mobileAPI.LoginServlet
  • java.util.List
  • jpa.controllers.exceptions.IllegalOrphanException
  • javax.persistence.criteria.CriteriaQuery
  • jpa.controllers.exceptions.NonexistentEntityException
  • javax.persistence.Query
  • javax.persistence.EntityManager
    • Copyright © 2018 www.massapicom. All rights reserved.
    All source code are property of their respective owners. Java is a trademark of Sun Microsystems, Inc and owned by ORACLE Inc. Contact coftware#gmail.com.