* Has <b>OK</b> if the correct substring position returned.
*/
public void _searchBackward() {
requiredMethod("setOptions()") ;
SearchResult res = oObj.searchBackward(str, endPos, startPos) ;
log.println("Result of searching '" + searchStr + "' substring in \n'" +
str + "' string (" + res.subRegExpressions + " matches):") ;
for (int i = 0; i < res.subRegExpressions; i++)