Package com.mysql.clusterj.jpatest.model

Examples of com.mysql.clusterj.jpatest.model.LongLongStringOid


        LongLongStringPK a;
        em = emf.createEntityManager();
        print("Removing " + NUMBER_OF_A + " instances of LongLongStringPK.");
        begin();
        for (int i = OFFSET_A; i < OFFSET_A + NUMBER_OF_A; ++i) {
            LongLongStringOid oid = new LongLongStringOid(i);
            a = em.find(LongLongStringPK.class, oid);
            if (a != null) {
                verify(oid, a);
                em.remove(a);
            }
        }
        commit();
        em.close();

        em = emf.createEntityManager();
        begin();
        print("Creating " + NUMBER_OF_A + " instances of LongLongStringPK.");
        for (int i = OFFSET_A; i < OFFSET_A + NUMBER_OF_A; ++i) {
            a = LongLongStringPK.create(i);
            em.persist(a);
        }
        commit();
        em.close();

        em = emf.createEntityManager();
        print("Finding " + NUMBER_OF_A + " instances of LongLongStringPK.");
        begin();
        for (int i = OFFSET_A; i < OFFSET_A + NUMBER_OF_A; ++i) {
            LongLongStringOid oid = new LongLongStringOid(i);
            a = em.find(LongLongStringPK.class, oid);
        }
        commit();
        em.close();
View Full Code Here


        em = emf.createEntityManager();
        print("Finding " + NUMBER_OF_A + " instances of LongLongStringPKOneMany.");
        begin();
        for (int i = OFFSET_A; i < OFFSET_A + NUMBER_OF_A; ++i) {
            LongLongStringOid oid = new LongLongStringOid(i);
            a = em.find(LongLongStringPKOneMany.class, oid);
        }
        print("Finding " + NUMBER_OF_B + " instances of LongLongStringFKManyOne.");
        for (int i = OFFSET_B; i < OFFSET_B + NUMBER_OF_B; ++i) {
            LongLongStringOid oid = new LongLongStringOid(i);
            LongLongStringFKManyOne b = em.find(LongLongStringFKManyOne.class, oid);
            print(b.toString());
        }
        commit();
        em.close();

        /** Update every other instance of B to refer to a different A. */
        em = emf.createEntityManager();
        print("Finding 1 instance of A.");
        begin();
        LongLongStringOid oid = new LongLongStringOid(OFFSET_A);
        a = em.find(LongLongStringPKOneMany.class, oid);
        print("Finding 2 instances of B.");
        for (int i = OFFSET_B; i < OFFSET_B + NUMBER_OF_B; i += 2) {
            oid = new LongLongStringOid(i);
            LongLongStringFKManyOne b = em.find(LongLongStringFKManyOne.class, oid);
            // update every other one
            b.setLongLongStringPKRelationship(a);
            print(b.toString());
        }
        print("After update: " + a0.toString());
        commit();
        em.close();

        em = emf.createEntityManager();
        print("Finding " + NUMBER_OF_A + " instances of A.");
        begin();
        for (int i = OFFSET_A; i < OFFSET_A + NUMBER_OF_A; ++i) {
            oid = new LongLongStringOid(i);
            a = em.find(LongLongStringPKOneMany.class, oid);
            as.add(a);
            print(a.toString());
        }
        print("Finding " + NUMBER_OF_B + " instances of B.");
        for (int i = OFFSET_B; i < OFFSET_B + NUMBER_OF_B; ++i) {
            oid = new LongLongStringOid(i);
            LongLongStringFKManyOne b = em.find(LongLongStringFKManyOne.class, oid);
            print(b.toString());
            if (0 == i%2) {
                errorIfNotEqual("Mismatch in relationship longLongStringPKRelationship",
                        as.get(0), b.getLongLongStringPKOneMany());
View Full Code Here

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